(x-1)(x+2)=x^2-16

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Solution for (x-1)(x+2)=x^2-16 equation:



(x-1)(x+2)=x^2-16
We move all terms to the left:
(x-1)(x+2)-(x^2-16)=0
We get rid of parentheses
-x^2+(x-1)(x+2)+16=0
We multiply parentheses ..
-x^2+(+x^2+2x-1x-2)+16=0
We add all the numbers together, and all the variables
-1x^2+(+x^2+2x-1x-2)+16=0
We get rid of parentheses
-1x^2+x^2+2x-1x-2+16=0
We add all the numbers together, and all the variables
x+14=0
We move all terms containing x to the left, all other terms to the right
x=-14

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